What are the solutions to the equation solvefor a,a^2-ab-12b^2=0 ?

The solutions to the equation solvefor a,a^2-ab-12b^2=0 are a=4b,a=-3b

Find the zeros of solvefor a,a^2-ab-12b^2=0

The zeros of solvefor a,a^2-ab-12b^2=0 are a=4b,a=-3b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

a, a^{2} - ab - 12 b^{2} = 0

a = 4 b, a = - 3 b

Solution steps

a^{2} - ab - 12 b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - ba - 12 b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - b ) \pm ( - b ) ^{2} - 4 \cdot 1 \cdot ( - 12 b ^{2} )}{2 \cdot 1}

Simplify

(- b)^{2} - 4 \cdot 1 \cdot (- 12 b^{2}) : 7 b

a_{1, 2} = \frac{- ( - b ) \pm 7 b}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - b ) + 7 b}{2 \cdot 1}, a_{2} = \frac{- ( - b ) - 7 b}{2 \cdot 1}

a = \frac{- ( - b ) + 7 b}{2 \cdot 1} : 4 b

a = \frac{- ( - b ) - 7 b}{2 \cdot 1} : - 3 b

The solutions to the quadratic equation are:

a = 4 b, a = - 3 b

2 y^{2} + y = 0

10 x^{2} = 45 - 68 x

[f (a)]^{2} = 5 x^{2} - x + 3

4 a^{2} x^{2} + a b^{2} x + 5 = 0

\frac{1}{2} x^{2} + 3 = 12

What are the solutions to the equation solvefor a,a^2-ab-12b^2=0 ?
The solutions to the equation solvefor a,a^2-ab-12b^2=0 are a=4b,a=-3b
Find the zeros of solvefor a,a^2-ab-12b^2=0
The zeros of solvefor a,a^2-ab-12b^2=0 are a=4b,a=-3b