What are the solutions to the equation 10x^2=45-68x ?

The solutions to the equation 10x^2=45-68x are x=(-34+sqrt(1606))/(10),x=-(34+sqrt(1606))/(10)

Find the zeros of 10x^2=45-68x

The zeros of 10x^2=45-68x are x=(-34+sqrt(1606))/(10),x=-(34+sqrt(1606))/(10)

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10 x^{2} = 45 - 68 x

x = \frac{- 34 + 1606}{10}, x = - \frac{34 + 1606}{10}

Decimal Notation

x = 0.60749 \dots, x = - 7.40749 \dots

Solution steps

10 x^{2} = 45 - 68 x

Move

68 x

to the left side

10 x^{2} + 68 x = 45

Move

45

to the left side

10 x^{2} + 68 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 68 \pm 6 8 ^{2} - 4 \cdot 10 ( - 45 )}{2 \cdot 10}

6 8^{2} - 4 \cdot 10 (- 45) = 21606

x_{1, 2} = \frac{- 68 \pm 2 1606}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 68 + 2 1606}{2 \cdot 10}, x_{2} = \frac{- 68 - 2 1606}{2 \cdot 10}

x = \frac{- 68 + 2 1606}{2 \cdot 10} : \frac{- 34 + 1606}{10}

x = \frac{- 68 - 2 1606}{2 \cdot 10} : - \frac{34 + 1606}{10}

The solutions to the quadratic equation are:

x = \frac{- 34 + 1606}{10}, x = - \frac{34 + 1606}{10}

[f (a)]^{2} = 5 x^{2} - x + 3

4 a^{2} x^{2} + a b^{2} x + 5 = 0

\frac{1}{2} x^{2} + 3 = 12

y, 9 y^{2} = z (z - 3)^{2}

- 6 x^{2} + 7 x = - 10

What are the solutions to the equation 10x^2=45-68x ?
The solutions to the equation 10x^2=45-68x are x=(-34+sqrt(1606))/(10),x=-(34+sqrt(1606))/(10)
Find the zeros of 10x^2=45-68x
The zeros of 10x^2=45-68x are x=(-34+sqrt(1606))/(10),x=-(34+sqrt(1606))/(10)