What are the solutions to the equation (x+7)^2-5(x+7)-14=0 ?

The solutions to the equation (x+7)^2-5(x+7)-14=0 are x=0,x=-9

Find the zeros of (x+7)^2-5(x+7)-14=0

The zeros of (x+7)^2-5(x+7)-14=0 are x=0,x=-9

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(x + 7)^{2} - 5 (x + 7) - 14 = 0

x = 0, x = - 9

Solution steps

(x + 7)^{2} - 5 (x + 7) - 14 = 0

Expand

(x + 7)^{2} - 5 (x + 7) - 14 : x^{2} + 9 x

x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 \cdot 1}, x_{2} = \frac{- 9 - 9}{2 \cdot 1}

x = \frac{- 9 + 9}{2 \cdot 1} : 0

x = \frac{- 9 - 9}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

x^{2} - 128 = 0

(38 - x)^{2} + (19 - x)^{2} = x^{2}

x^{2} + 10 x + 20 = 0

7 x^{2} - x + 8 = 0

(x + 1)^{2} = 8

What are the solutions to the equation (x+7)^2-5(x+7)-14=0 ?
The solutions to the equation (x+7)^2-5(x+7)-14=0 are x=0,x=-9
Find the zeros of (x+7)^2-5(x+7)-14=0
The zeros of (x+7)^2-5(x+7)-14=0 are x=0,x=-9