What are the solutions to the equation (x+1)^2=8 ?

The solutions to the equation (x+1)^2=8 are x=2sqrt(2)-1,x=-2sqrt(2)-1

Find the zeros of (x+1)^2=8

The zeros of (x+1)^2=8 are x=2sqrt(2)-1,x=-2sqrt(2)-1

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(x + 1)^{2} = 8

x = 22 - 1, x = - 22 - 1

Decimal Notation

x = 1.82842 \dots, x = - 3.82842 \dots

Solution steps

(x + 1)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 8 : x = 22 - 1

Solve

x + 1 = - 8 : x = - 22 - 1

The solutions to the quadratic equation are:

x = 22 - 1, x = - 22 - 1

5 x^{2} = 27 x + 18

x, x^{2} - y^{2} - 5 x y - 1 = 0

q^{2} + 3 q - 19 = - 5

x, w = - 3 x^{2} + 5

q^{2} - 30 q + 200 = 0

What are the solutions to the equation (x+1)^2=8 ?
The solutions to the equation (x+1)^2=8 are x=2sqrt(2)-1,x=-2sqrt(2)-1
Find the zeros of (x+1)^2=8
The zeros of (x+1)^2=8 are x=2sqrt(2)-1,x=-2sqrt(2)-1