What are the solutions to the equation x^2+8x+16-4a^2=0 ?

The solutions to the equation x^2+8x+16-4a^2=0 are x=-2a-4,x=2a-4

Find the zeros of x^2+8x+16-4a^2=0

The zeros of x^2+8x+16-4a^2=0 are x=-2a-4,x=2a-4

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x^{2} + 8 x + 16 - 4 a^{2} = 0

x = - 2 a - 4, x = 2 a - 4

Solution steps

x^{2} + 8 x + 16 - 4 a^{2} = 0

Factor

x^{2} + 8 x + 16 - 4 a^{2} : (x + 2 a + 4) (x - 2 a + 4)

(x + 2 a + 4) (x - 2 a + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 a + 4 = 0 or x - 2 a + 4 = 0

Solve

x + 2 a + 4 = 0 : x = - 2 a - 4

Solve

x - 2 a + 4 = 0 : x = 2 a - 4

The solutions to the quadratic equation are:

x = - 2 a - 4, x = 2 a - 4

4.68 X^{2} - 15.5 X + 12.43 = 0

(x + 4) (x + 5) = 6

25 = π r^{2}

x^{2} - 10 x - 167 = 0

8 a^{2} + 2 a - 6 = 0

What are the solutions to the equation x^2+8x+16-4a^2=0 ?
The solutions to the equation x^2+8x+16-4a^2=0 are x=-2a-4,x=2a-4
Find the zeros of x^2+8x+16-4a^2=0
The zeros of x^2+8x+16-4a^2=0 are x=-2a-4,x=2a-4