What are the solutions to the equation 25=pir^2 ?

The solutions to the equation 25=pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))

Find the zeros of 25=pir^2

The zeros of 25=pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))

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25 = π r^{2}

r = \frac{5}{π}, r = - \frac{5}{π}

Decimal Notation

r = 2.82094 \dots, r = - 2.82094 \dots

Solution steps

25 = π r^{2}

Switch sides

π r^{2} = 25

Divide both sides by

π

r^{2} = \frac{25}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{25}{π}, r = - \frac{25}{π}

\frac{25}{π} = \frac{5}{π}

- \frac{25}{π} = - \frac{5}{π}

r = \frac{5}{π}, r = - \frac{5}{π}

x^{2} - 10 x - 167 = 0

8 a^{2} + 2 a - 6 = 0

x^{2} = - 2 x + 63

5 y^{2} = - y + 4

- 3 x^{2} - 8 x + 9 = 0

What are the solutions to the equation 25=pir^2 ?
The solutions to the equation 25=pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))
Find the zeros of 25=pir^2
The zeros of 25=pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))