What are the solutions to the equation 5y^2=-y+4 ?

The solutions to the equation 5y^2=-y+4 are y= 4/5 ,y=-1

Find the zeros of 5y^2=-y+4

The zeros of 5y^2=-y+4 are y= 4/5 ,y=-1

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5 y^{2} = - y + 4

y = \frac{4}{5}, y = - 1

Decimal Notation

y = 0.8, y = - 1

Solution steps

5 y^{2} = - y + 4

Move

4

to the left side

5 y^{2} - 4 = - y

Move

y

to the left side

5 y^{2} - 4 + y = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} + y - 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 4) = 9

y_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 1 + 9}{2 \cdot 5}, y_{2} = \frac{- 1 - 9}{2 \cdot 5}

y = \frac{- 1 + 9}{2 \cdot 5} : \frac{4}{5}

y = \frac{- 1 - 9}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

y = \frac{4}{5}, y = - 1

- 3 x^{2} - 8 x + 9 = 0

b^{2} - 10 b + 10 = - 6

x^{2} + x - 72 = 0

x, x (100 - x - 2 y) = 0

7 x^{2} - 10 = 0

What are the solutions to the equation 5y^2=-y+4 ?
The solutions to the equation 5y^2=-y+4 are y= 4/5 ,y=-1
Find the zeros of 5y^2=-y+4
The zeros of 5y^2=-y+4 are y= 4/5 ,y=-1