What are the solutions to the equation x^2+5x-10=0 ?

The solutions to the equation x^2+5x-10=0 are x=(-5+sqrt(65))/2 ,x=(-5-sqrt(65))/2

Find the zeros of x^2+5x-10=0

The zeros of x^2+5x-10=0 are x=(-5+sqrt(65))/2 ,x=(-5-sqrt(65))/2

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x^{2} + 5 x - 10 = 0

x = \frac{- 5 + 65}{2}, x = \frac{- 5 - 65}{2}

Solution steps

x^{2} + 5 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 10) = 65

x_{1, 2} = \frac{- 5 \pm 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 65}{2 \cdot 1}, x_{2} = \frac{- 5 - 65}{2 \cdot 1}

x = \frac{- 5 + 65}{2 \cdot 1} : \frac{- 5 + 65}{2}

x = \frac{- 5 - 65}{2 \cdot 1} : \frac{- 5 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 65}{2}, x = \frac{- 5 - 65}{2}

12 x^{2} u + 3 x^{2} v + 28 y u + 7 y v

245 m^{2} n - 210 m n^{2} + 45 n^{3}

- x + 6 > - (2 x + 4)

- 2 (r - 13) + 10 > 6

f^{- 1} (6)

What are the solutions to the equation x^2+5x-10=0 ?
The solutions to the equation x^2+5x-10=0 are x=(-5+sqrt(65))/2 ,x=(-5-sqrt(65))/2
Find the zeros of x^2+5x-10=0
The zeros of x^2+5x-10=0 are x=(-5+sqrt(65))/2 ,x=(-5-sqrt(65))/2