What are the solutions to the equation x^2=56-x ?

The solutions to the equation x^2=56-x are x=7,x=-8

Find the zeros of x^2=56-x

The zeros of x^2=56-x are x=7,x=-8

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x^{2} = 56 - x

x = 7, x = - 8

Solution steps

x^{2} = 56 - x

Move

x

to the left side

x^{2} + x = 56

Move

56

to the left side

x^{2} + x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 56) = 15

x_{1, 2} = \frac{- 1 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 15}{2 \cdot 1}, x_{2} = \frac{- 1 - 15}{2 \cdot 1}

x = \frac{- 1 + 15}{2 \cdot 1} : 7

x = \frac{- 1 - 15}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 7, x = - 8

\frac{3}{2} (4 x^{2} - 20 x + 60) = 0

x^{2} - 5 a + 8 x = 0

t, g (t - 1) = 5 - (t - 1)^{2}

x, f (x - 2) = x^{2} + 4 x + 7

2 x^{2} - 3 x + 1 = 38

What are the solutions to the equation x^2=56-x ?
The solutions to the equation x^2=56-x are x=7,x=-8
Find the zeros of x^2=56-x
The zeros of x^2=56-x are x=7,x=-8