What are the solutions to the equation completesquare-x^2+10x-28 ?

The solutions to the equation completesquare-x^2+10x-28 are -(x-5)^2-3

Find the zeros of completesquare-x^2+10x-28

The zeros of completesquare-x^2+10x-28 are -(x-5)^2-3

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complete the square

- x^{2} + 10 x - 28

- (x - 5)^{2} - 3

Solution steps

- x^{2} + 10 x - 28

Write

- x^{2} + 10 x - 28

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} - 10 x + 28)

2 a = - 10 : a = - 5

Add and subtract

(- 5)^{2}

- (x^{2} - 10 x + 28 + (- 5)^{2} - (- 5)^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 10 x + (- 5)^{2} = (x - 5)^{2}

- ((x - 5)^{2} + 28 - (- 5)^{2})

Simplify

- (x - 5)^{2} - 3

0 = x^{2} + 25

r^{2} - 12 r + 32 = 0

x, 0 = x^{2} + x - 12

x, y (x^{2} - 4) = 1 - x^{2}

6 x^{2} - 135 = 3 x^{2}

What are the solutions to the equation completesquare-x^2+10x-28 ?
The solutions to the equation completesquare-x^2+10x-28 are -(x-5)^2-3
Find the zeros of completesquare-x^2+10x-28
The zeros of completesquare-x^2+10x-28 are -(x-5)^2-3