What are the solutions to the equation (5x+8)(12-12x)=0 ?

The solutions to the equation (5x+8)(12-12x)=0 are x=-8/5 ,x=1

Find the zeros of (5x+8)(12-12x)=0

The zeros of (5x+8)(12-12x)=0 are x=-8/5 ,x=1

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(5 x + 8) (12 - 12 x) = 0

x = - \frac{8}{5}, x = 1

Decimal Notation

x = - 1.6, x = 1

Solution steps

(5 x + 8) (12 - 12 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 8 = 0 or 12 - 12 x = 0

Solve

5 x + 8 = 0 : x = - \frac{8}{5}

Solve

12 - 12 x = 0 : x = 1

The solutions to the quadratic equation are:

x = - \frac{8}{5}, x = 1

6 = (3 x + 1)^{2}

12 x^{2} - 10 x + 5 = 0

(4 x - 1)^{2} - 123 x = (x + 5) (x - 8)

3 x^{2} + 10 x = 48

4.5 t^{2} - 27 t + 22.5 = 0

What are the solutions to the equation (5x+8)(12-12x)=0 ?
The solutions to the equation (5x+8)(12-12x)=0 are x=-8/5 ,x=1
Find the zeros of (5x+8)(12-12x)=0
The zeros of (5x+8)(12-12x)=0 are x=-8/5 ,x=1