What are the solutions to the equation 14=3x-x^2 ?

The solutions to the equation 14=3x-x^2 are x= 3/2-i(sqrt(47))/2 ,x= 3/2+i(sqrt(47))/2

Find the zeros of 14=3x-x^2

The zeros of 14=3x-x^2 are x= 3/2-i(sqrt(47))/2 ,x= 3/2+i(sqrt(47))/2

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14 = 3 x - x^{2}

x = \frac{3}{2} - i \frac{47}{2}, x = \frac{3}{2} + i \frac{47}{2}

Solution steps

14 = 3 x - x^{2}

Switch sides

3 x - x^{2} = 14

Move

14

to the left side

3 x - x^{2} - 14 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 3 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 14 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 14) : 47 i

x_{1, 2} = \frac{- 3 \pm 47 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 47 i}{2 ( - 1 )}, x_{2} = \frac{- 3 - 47 i}{2 ( - 1 )}

x = \frac{- 3 + 47 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{47}{2}

x = \frac{- 3 - 47 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{47}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} - i \frac{47}{2}, x = \frac{3}{2} + i \frac{47}{2}

(\frac{7}{25})^{2} + y^{2} = 1

x^{2} - 8 x + 1 = 0

k^{2} - 6 k + 5 = 0

x^{2} + 2 x + 1 = 5 x + 41

35 x^{2} - 2 - 9 x = 0

What are the solutions to the equation 14=3x-x^2 ?
The solutions to the equation 14=3x-x^2 are x= 3/2-i(sqrt(47))/2 ,x= 3/2+i(sqrt(47))/2
Find the zeros of 14=3x-x^2
The zeros of 14=3x-x^2 are x= 3/2-i(sqrt(47))/2 ,x= 3/2+i(sqrt(47))/2