What are the solutions to the equation k^2-6k+5=0 ?

The solutions to the equation k^2-6k+5=0 are k=5,k=1

Find the zeros of k^2-6k+5=0

The zeros of k^2-6k+5=0 are k=5,k=1

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k^{2} - 6 k + 5 = 0

k = 5, k = 1

Solution steps

k^{2} - 6 k + 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

k_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, k_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

k = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

k = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

k = 5, k = 1

x^{2} + 2 x + 1 = 5 x + 41

35 x^{2} - 2 - 9 x = 0

2 x^{2} + 4 x - 22 = 0

9 x^{2} - x + 2 = 0

x, 2 x^{2} + 5 x = 8

What are the solutions to the equation k^2-6k+5=0 ?
The solutions to the equation k^2-6k+5=0 are k=5,k=1
Find the zeros of k^2-6k+5=0
The zeros of k^2-6k+5=0 are k=5,k=1