What are the solutions to the equation 9x^2-x+2=0 ?

The solutions to the equation 9x^2-x+2=0 are x= 1/18+i(sqrt(71))/(18),x= 1/18-i(sqrt(71))/(18)

Find the zeros of 9x^2-x+2=0

The zeros of 9x^2-x+2=0 are x= 1/18+i(sqrt(71))/(18),x= 1/18-i(sqrt(71))/(18)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - x + 2 = 0

x = \frac{1}{18} + i \frac{71}{18}, x = \frac{1}{18} - i \frac{71}{18}

Solution steps

9 x^{2} - x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

(- 1)^{2} - 4 \cdot 9 \cdot 2 : 71 i

x_{1, 2} = \frac{- ( - 1 ) \pm 71 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 71 i}{2 \cdot 9}, x_{2} = \frac{- ( - 1 ) - 71 i}{2 \cdot 9}

x = \frac{- ( - 1 ) + 71 i}{2 \cdot 9} : \frac{1}{18} + i \frac{71}{18}

x = \frac{- ( - 1 ) - 71 i}{2 \cdot 9} : \frac{1}{18} - i \frac{71}{18}

The solutions to the quadratic equation are:

x = \frac{1}{18} + i \frac{71}{18}, x = \frac{1}{18} - i \frac{71}{18}

x, 2 x^{2} + 5 x = 8

y - 3 = y^{2} - 2 y - 13

(3 x + 4) (5 - \frac{x}{2}) = 0

x^{2} - 9 x = 8

9 x^{2} - 6 x - 3

What are the solutions to the equation 9x^2-x+2=0 ?
The solutions to the equation 9x^2-x+2=0 are x= 1/18+i(sqrt(71))/(18),x= 1/18-i(sqrt(71))/(18)
Find the zeros of 9x^2-x+2=0
The zeros of 9x^2-x+2=0 are x= 1/18+i(sqrt(71))/(18),x= 1/18-i(sqrt(71))/(18)