What are the solutions to the equation completesquare 2x^2+7x-4=0 ?

The solutions to the equation completesquare 2x^2+7x-4=0 are x= 1/2 ,x=-4

Find the zeros of completesquare 2x^2+7x-4=0

The zeros of completesquare 2x^2+7x-4=0 are x= 1/2 ,x=-4

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2 x^{2} + 7 x - 4 = 0

x = \frac{1}{2}, x = - 4

Decimal Notation

x = 0.5, x = - 4

Solution steps

2 x^{2} + 7 x - 4 = 0

Move

4

to the right side

2 x^{2} + 7 x = 4

Divide both sides by

2

\frac{2 x ^{2} + 7 x}{2} = \frac{4}{2}

x^{2} + \frac{7 x}{2} = 2

Rewrite in the form

(x + a)^{2} = b

(x + \frac{7}{4})^{2} = \frac{81}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{7}{4} = \frac{81}{16} : x = \frac{1}{2}

Solve

x + \frac{7}{4} = - \frac{81}{16} : x = - 4

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 4

6 - 5 a^{2} = - 6 a + 4

A = - 5 x^{2} + 78 x + 21

x^{2} + 99 = 16 x + 10

x, y = x^{2} - 6 x

x, f (x - 2) = x^{2} + 9 x + 5

What are the solutions to the equation completesquare 2x^2+7x-4=0 ?
The solutions to the equation completesquare 2x^2+7x-4=0 are x= 1/2 ,x=-4
Find the zeros of completesquare 2x^2+7x-4=0
The zeros of completesquare 2x^2+7x-4=0 are x= 1/2 ,x=-4