What are the solutions to the equation 8000=3x^2+2x+400 ?

The solutions to the equation 8000=3x^2+2x+400 are x=50,x=-152/3

Find the zeros of 8000=3x^2+2x+400

The zeros of 8000=3x^2+2x+400 are x=50,x=-152/3

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8000 = 3 x^{2} + 2 x + 400

x = 50, x = - \frac{152}{3}

Decimal Notation

x = 50, x = - 50.66666 \dots

Solution steps

8000 = 3 x^{2} + 2 x + 400

Switch sides

3 x^{2} + 2 x + 400 = 8000

Move

8000

to the left side

3 x^{2} + 2 x - 7600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 7600 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 7600) = 302

x_{1, 2} = \frac{- 2 \pm 302}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 302}{2 \cdot 3}, x_{2} = \frac{- 2 - 302}{2 \cdot 3}

x = \frac{- 2 + 302}{2 \cdot 3} : 50

x = \frac{- 2 - 302}{2 \cdot 3} : - \frac{152}{3}

The solutions to the quadratic equation are:

x = 50, x = - \frac{152}{3}

(c - 2) (c + 8) = 7

5 (x + 4)^{2} = 90

3 x^{2} + 3 = 6

(x + 4)^{2} = - 2

x^{2} + 4 x - 32 = 0

What are the solutions to the equation 8000=3x^2+2x+400 ?
The solutions to the equation 8000=3x^2+2x+400 are x=50,x=-152/3
Find the zeros of 8000=3x^2+2x+400
The zeros of 8000=3x^2+2x+400 are x=50,x=-152/3