What are the solutions to the equation (k+7)^2=81 ?

The solutions to the equation (k+7)^2=81 are k=2,k=-16

Find the zeros of (k+7)^2=81

The zeros of (k+7)^2=81 are k=2,k=-16

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(k + 7)^{2} = 81

k = 2, k = - 16

Solution steps

(k + 7)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k + 7 = 81 : k = 2

Solve

k + 7 = - 81 : k = - 16

The solutions to the quadratic equation are:

k = 2, k = - 16

2 (t^{2} + 3) = t^{2} + 55

(x + 1)^{2} - 12 = 0

x^{2} - 9995 x - 50000 = 0

m^{2} + 16 m = 4

x^{2} + 19 x + 48 = 0

What are the solutions to the equation (k+7)^2=81 ?
The solutions to the equation (k+7)^2=81 are k=2,k=-16
Find the zeros of (k+7)^2=81
The zeros of (k+7)^2=81 are k=2,k=-16