What are the solutions to the equation 20^2+16^2=x^2 ?

The solutions to the equation 20^2+16^2=x^2 are x=4sqrt(41),x=-4sqrt(41)

Find the zeros of 20^2+16^2=x^2

The zeros of 20^2+16^2=x^2 are x=4sqrt(41),x=-4sqrt(41)

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2 0^{2} + 1 6^{2} = x^{2}

x = 441, x = - 441

Decimal Notation

x = 25.61249 \dots, x = - 25.61249 \dots

Solution steps

2 0^{2} + 1 6^{2} = x^{2}

Switch sides

x^{2} = 2 0^{2} + 1 6^{2}

Simplify

2 0^{2} + 1 6^{2} : 656

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 656, x = - 656

656 = 441

- 656 = - 441

x = 441, x = - 441

1 3^{2} = x^{2} + 4^{2}

2 x (x - 4) = 3

5 x^{2} + 10 x - 895 = 0

11 x^{2} - 14 x - 16 = 0

(2 x - 3)^{2} + 4 = 5 (2 x + 9)

What are the solutions to the equation 20^2+16^2=x^2 ?
The solutions to the equation 20^2+16^2=x^2 are x=4sqrt(41),x=-4sqrt(41)
Find the zeros of 20^2+16^2=x^2
The zeros of 20^2+16^2=x^2 are x=4sqrt(41),x=-4sqrt(41)