What are the solutions to the equation 24x^2=3 ?

The solutions to the equation 24x^2=3 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))

Find the zeros of 24x^2=3

The zeros of 24x^2=3 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))

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24 x^{2} = 3

x = \frac{1}{2 2}, x = - \frac{1}{2 2}

Decimal Notation

x = 0.35355 \dots, x = - 0.35355 \dots

Solution steps

24 x^{2} = 3

Divide both sides by

24

x^{2} = \frac{1}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{8}, x = - \frac{1}{8}

\frac{1}{8} = \frac{1}{2 2}

- \frac{1}{8} = - \frac{1}{2 2}

x = \frac{1}{2 2}, x = - \frac{1}{2 2}

7 x (x + 4) + 6 = 5

x (5 x - 8) = - 3

2 (x + 4)^{2} = 9

x^{2} - 5 (x + 6) = - 5 x

\frac{2}{5} x^{2} + 63 = 13

What are the solutions to the equation 24x^2=3 ?
The solutions to the equation 24x^2=3 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))
Find the zeros of 24x^2=3
The zeros of 24x^2=3 are x= 1/(2sqrt(2)),x=-1/(2sqrt(2))