What are the solutions to the equation a^2-12a+20=0 ?

The solutions to the equation a^2-12a+20=0 are a=10,a=2

Find the zeros of a^2-12a+20=0

The zeros of a^2-12a+20=0 are a=10,a=2

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a^{2} - 12 a + 20 = 0

a = 10, a = 2

Solution steps

a^{2} - 12 a + 20 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 20 = 8

a_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 1}, a_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 1}

a = \frac{- ( - 12 ) + 8}{2 \cdot 1} : 10

a = \frac{- ( - 12 ) - 8}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

a = 10, a = 2

x^{2} + 2 x = - x + 4

(x - 4)^{2} - 13 = 0

x, x^{2} y y^{1} = e^{y}

10 x^{2} - 30 = - 20 x

3 x^{2} + 2 x = 5

What are the solutions to the equation a^2-12a+20=0 ?
The solutions to the equation a^2-12a+20=0 are a=10,a=2
Find the zeros of a^2-12a+20=0
The zeros of a^2-12a+20=0 are a=10,a=2