What are the solutions to the equation -3x^2+36x-120=-15 ?

The solutions to the equation -3x^2+36x-120=-15 are x=5,x=7

Find the zeros of -3x^2+36x-120=-15

The zeros of -3x^2+36x-120=-15 are x=5,x=7

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- 3 x^{2} + 36 x - 120 = - 15

x = 5, x = 7

Solution steps

- 3 x^{2} + 36 x - 120 = - 15

Move

15

to the left side

- 3 x^{2} + 36 x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 3 ) ( - 105 )}{2 ( - 3 )}

3 6^{2} - 4 (- 3) (- 105) = 6

x_{1, 2} = \frac{- 36 \pm 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 36 + 6}{2 ( - 3 )}, x_{2} = \frac{- 36 - 6}{2 ( - 3 )}

x = \frac{- 36 + 6}{2 ( - 3 )} : 5

x = \frac{- 36 - 6}{2 ( - 3 )} : 7

The solutions to the quadratic equation are:

x = 5, x = 7

33 z + 7 z^{2} = 10

x^{2} + 52 x + 100 = 0

x^{2} + 9 = 3 x

7 x^{2} - 22 x + 16 = 0

2 (3 x^{2} - x) = 8 - 3 x

What are the solutions to the equation -3x^2+36x-120=-15 ?
The solutions to the equation -3x^2+36x-120=-15 are x=5,x=7
Find the zeros of -3x^2+36x-120=-15
The zeros of -3x^2+36x-120=-15 are x=5,x=7