What are the solutions to the equation x^2+12=48 ?

The solutions to the equation x^2+12=48 are x=6,x=-6

Find the zeros of x^2+12=48

The zeros of x^2+12=48 are x=6,x=-6

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x^{2} + 12 = 48

x = 6, x = - 6

Solution steps

x^{2} + 12 = 48

Move

12

to the right side

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

9 = - 3 x^{2} + 5 x

(x + 19)^{2} = - 9

3 t^{2} = 12 t - 15

x^{2} - 3 x - 2 = 0

x^{2} + 4 x + 11

What are the solutions to the equation x^2+12=48 ?
The solutions to the equation x^2+12=48 are x=6,x=-6
Find the zeros of x^2+12=48
The zeros of x^2+12=48 are x=6,x=-6