What are the solutions to the equation (5x-11)^2+6=150 ?

The solutions to the equation (5x-11)^2+6=150 are x= 23/5 ,x=-1/5

Find the zeros of (5x-11)^2+6=150

The zeros of (5x-11)^2+6=150 are x= 23/5 ,x=-1/5

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(5 x - 11)^{2} + 6 = 150

x = \frac{23}{5}, x = - \frac{1}{5}

Decimal Notation

x = 4.6, x = - 0.2

Solution steps

(5 x - 11)^{2} + 6 = 150

Move

6

to the right side

(5 x - 11)^{2} = 144

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 11 = 144 : x = \frac{23}{5}

Solve

5 x - 11 = - 144 : x = - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{23}{5}, x = - \frac{1}{5}

x, y (x^{2} + 1) = 1

- x^{2} + 2 x + 63 = 0

3 u^{2} - 5 u - 2 = 0

3 (y - 1)^{2} + 5 y = 3

(x - 5) (x + 1) = - 8

What are the solutions to the equation (5x-11)^2+6=150 ?
The solutions to the equation (5x-11)^2+6=150 are x= 23/5 ,x=-1/5
Find the zeros of (5x-11)^2+6=150
The zeros of (5x-11)^2+6=150 are x= 23/5 ,x=-1/5