What are the solutions to the equation 3x^2+6x+4=0 ?

The solutions to the equation 3x^2+6x+4=0 are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3

Find the zeros of 3x^2+6x+4=0

The zeros of 3x^2+6x+4=0 are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3

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3 x^{2} + 6 x + 4 = 0

x = - 1 + i \frac{3}{3}, x = - 1 - i \frac{3}{3}

Solution steps

3 x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 4 : 23 i

x_{1, 2} = \frac{- 6 \pm 2 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 3 i}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 3 i}{2 \cdot 3}

x = \frac{- 6 + 2 3 i}{2 \cdot 3} : - 1 + i \frac{3}{3}

x = \frac{- 6 - 2 3 i}{2 \cdot 3} : - 1 - i \frac{3}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{3}{3}, x = - 1 - i \frac{3}{3}

4 x + 3 > 15 or - 6 x \geq 12

\frac{2 x ^{- 2} y}{7 x ^{3} y ^{2}} \cdot \frac{14 x ^{5} y ^{3}}{x ^{0} y ^{5}}

x^{2} - 4 x - 1

7 x + 5 < - 9

9 x - 8 = - 2

What are the solutions to the equation 3x^2+6x+4=0 ?
The solutions to the equation 3x^2+6x+4=0 are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3
Find the zeros of 3x^2+6x+4=0
The zeros of 3x^2+6x+4=0 are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3