What are the solutions to the equation 7m+m^2=-4 ?

The solutions to the equation 7m+m^2=-4 are m=(-7+sqrt(33))/2 ,m=(-7-sqrt(33))/2

Find the zeros of 7m+m^2=-4

The zeros of 7m+m^2=-4 are m=(-7+sqrt(33))/2 ,m=(-7-sqrt(33))/2

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7 m + m^{2} = - 4

m = \frac{- 7 + 33}{2}, m = \frac{- 7 - 33}{2}

Decimal Notation

m = - 0.62771 \dots, m = - 6.37228 \dots

Solution steps

7 m + m^{2} = - 4

Move

4

to the left side

7 m + m^{2} + 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

m^{2} + 7 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 4 = 33

m_{1, 2} = \frac{- 7 \pm 33}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 7 + 33}{2 \cdot 1}, m_{2} = \frac{- 7 - 33}{2 \cdot 1}

m = \frac{- 7 + 33}{2 \cdot 1} : \frac{- 7 + 33}{2}

m = \frac{- 7 - 33}{2 \cdot 1} : \frac{- 7 - 33}{2}

The solutions to the quadratic equation are:

m = \frac{- 7 + 33}{2}, m = \frac{- 7 - 33}{2}

3 x = x^{2} - 1

3 x = x^{2} + 7

2 x (x - 3) = 5 (7 x - 10) - 8 x^{2} - 20 x + 25

x, x^{2} + 2 x y = c

y^{2} - 10 y + 22 = 0

What are the solutions to the equation 7m+m^2=-4 ?
The solutions to the equation 7m+m^2=-4 are m=(-7+sqrt(33))/2 ,m=(-7-sqrt(33))/2
Find the zeros of 7m+m^2=-4
The zeros of 7m+m^2=-4 are m=(-7+sqrt(33))/2 ,m=(-7-sqrt(33))/2