What are the solutions to the equation w(w-4)=-8 ?

The solutions to the equation w(w-4)=-8 are w=2+2i,w=2-2i

Find the zeros of w(w-4)=-8

The zeros of w(w-4)=-8 are w=2+2i,w=2-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

w (w - 4) = - 8

w = 2 + 2 i, w = 2 - 2 i

Solution steps

w (w - 4) = - 8

Expand

w (w - 4) : w^{2} - 4 w

w^{2} - 4 w = - 8

Move

8

to the left side

w^{2} - 4 w + 8 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 8 : 4 i

w_{1, 2} = \frac{- ( - 4 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 4 ) + 4 i}{2 \cdot 1}, w_{2} = \frac{- ( - 4 ) - 4 i}{2 \cdot 1}

w = \frac{- ( - 4 ) + 4 i}{2 \cdot 1} : 2 + 2 i

w = \frac{- ( - 4 ) - 4 i}{2 \cdot 1} : 2 - 2 i

The solutions to the quadratic equation are:

w = 2 + 2 i, w = 2 - 2 i

- \frac{x ^{2}}{2} + x = - 1.5

y^{2} - 19 = 0

10 x^{2} - 7 x = - 2 x^{2} + 8 x

x^{2} + x = 2 x + 6

x, y = 3 x - x^{2}

What are the solutions to the equation w(w-4)=-8 ?
The solutions to the equation w(w-4)=-8 are w=2+2i,w=2-2i
Find the zeros of w(w-4)=-8
The zeros of w(w-4)=-8 are w=2+2i,w=2-2i