What are the solutions to the equation 2m^2+5m+3=0 ?

The solutions to the equation 2m^2+5m+3=0 are m=-1,m=-3/2

Find the zeros of 2m^2+5m+3=0

The zeros of 2m^2+5m+3=0 are m=-1,m=-3/2

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2 m^{2} + 5 m + 3 = 0

m = - 1, m = - \frac{3}{2}

Decimal Notation

m = - 1, m = - 1.5

Solution steps

2 m^{2} + 5 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 3 = 1

m_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 5 + 1}{2 \cdot 2}, m_{2} = \frac{- 5 - 1}{2 \cdot 2}

m = \frac{- 5 + 1}{2 \cdot 2} : - 1

m = \frac{- 5 - 1}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

m = - 1, m = - \frac{3}{2}

x^{2} - 4 \cdot (- 5) = 0

a, a (18 - 13 a) + 166 = 0

- 6 + 8 x - 3 x^{2} = 3

y, 9 a y^{2} = x (3 a - x)^{2}

x^{2} - 8 x + 6

What are the solutions to the equation 2m^2+5m+3=0 ?
The solutions to the equation 2m^2+5m+3=0 are m=-1,m=-3/2
Find the zeros of 2m^2+5m+3=0
The zeros of 2m^2+5m+3=0 are m=-1,m=-3/2