What are the solutions to the equation -6+8x-3x^2=3 ?

The solutions to the equation -6+8x-3x^2=3 are x= 4/3-i(sqrt(11))/3 ,x= 4/3+i(sqrt(11))/3

Find the zeros of -6+8x-3x^2=3

The zeros of -6+8x-3x^2=3 are x= 4/3-i(sqrt(11))/3 ,x= 4/3+i(sqrt(11))/3

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- 6 + 8 x - 3 x^{2} = 3

x = \frac{4}{3} - i \frac{11}{3}, x = \frac{4}{3} + i \frac{11}{3}

Solution steps

- 6 + 8 x - 3 x^{2} = 3

Move

3

to the left side

- 3 x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 3 ) ( - 9 )}{2 ( - 3 )}

Simplify

8^{2} - 4 (- 3) (- 9) : 211 i

x_{1, 2} = \frac{- 8 \pm 2 11 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 11 i}{2 ( - 3 )}, x_{2} = \frac{- 8 - 2 11 i}{2 ( - 3 )}

x = \frac{- 8 + 2 11 i}{2 ( - 3 )} : \frac{4}{3} - i \frac{11}{3}

x = \frac{- 8 - 2 11 i}{2 ( - 3 )} : \frac{4}{3} + i \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3} - i \frac{11}{3}, x = \frac{4}{3} + i \frac{11}{3}

y, 9 a y^{2} = x (3 a - x)^{2}

x^{2} - 8 x + 6

2 x^{2} + 6 x

x, ln (y - 2) = x^{2} + 2

3 t^{2} - 12 = 12 t

What are the solutions to the equation -6+8x-3x^2=3 ?
The solutions to the equation -6+8x-3x^2=3 are x= 4/3-i(sqrt(11))/3 ,x= 4/3+i(sqrt(11))/3
Find the zeros of -6+8x-3x^2=3
The zeros of -6+8x-3x^2=3 are x= 4/3-i(sqrt(11))/3 ,x= 4/3+i(sqrt(11))/3