What are the solutions to the equation (x+4)(x-7)=-30 ?

The solutions to the equation (x+4)(x-7)=-30 are x=2,x=1

Find the zeros of (x+4)(x-7)=-30

The zeros of (x+4)(x-7)=-30 are x=2,x=1

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(x + 4) (x - 7) = - 30

x = 2, x = 1

Solution steps

(x + 4) (x - 7) = - 30

Expand

(x + 4) (x - 7) : x^{2} - 3 x - 28

x^{2} - 3 x - 28 = - 30

Move

30

to the left side

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

x, 2 y - x^{2} = x y

y, 2 x y + 5 y^{2} = 4

5 t^{2} + 14 t - 3 = 0

100 = (x - 1) (200 - 40 x)

\frac{4 a}{9} a = 5

What are the solutions to the equation (x+4)(x-7)=-30 ?
The solutions to the equation (x+4)(x-7)=-30 are x=2,x=1
Find the zeros of (x+4)(x-7)=-30
The zeros of (x+4)(x-7)=-30 are x=2,x=1