What are the solutions to the equation 5x^2=24 ?

The solutions to the equation 5x^2=24 are x=(2sqrt(6))/(sqrt(5)),x=-(2sqrt(6))/(sqrt(5))

Find the zeros of 5x^2=24

The zeros of 5x^2=24 are x=(2sqrt(6))/(sqrt(5)),x=-(2sqrt(6))/(sqrt(5))

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5 x^{2} = 24

x = \frac{2 6}{5}, x = - \frac{2 6}{5}

Decimal Notation

x = 2.19089 \dots, x = - 2.19089 \dots

Solution steps

5 x^{2} = 24

Divide both sides by

5

x^{2} = \frac{24}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{24}{5}, x = - \frac{24}{5}

\frac{24}{5} = \frac{2 6}{5}

- \frac{24}{5} = - \frac{2 6}{5}

x = \frac{2 6}{5}, x = - \frac{2 6}{5}

12 x^{2} + 24 x + 8 = 0

(6 - x) (x + 1) = 0

0 = 210 + 205.06 x - 4.9 x^{2}

(x - 1)^{2} - 64 = 0

2 (x + 1)^{2} - 3 (x + 1) + 1 = 0

What are the solutions to the equation 5x^2=24 ?
The solutions to the equation 5x^2=24 are x=(2sqrt(6))/(sqrt(5)),x=-(2sqrt(6))/(sqrt(5))
Find the zeros of 5x^2=24
The zeros of 5x^2=24 are x=(2sqrt(6))/(sqrt(5)),x=-(2sqrt(6))/(sqrt(5))