What are the solutions to the equation 0=2x^2-x-6 ?

The solutions to the equation 0=2x^2-x-6 are x=2,x=-3/2

Find the zeros of 0=2x^2-x-6

The zeros of 0=2x^2-x-6 are x=2,x=-3/2

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0 = 2 x^{2} - x - 6

x = 2, x = - \frac{3}{2}

Decimal Notation

x = 2, x = - 1.5

Solution steps

0 = 2 x^{2} - x - 6

Switch sides

2 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 2}

x = \frac{- ( - 1 ) + 7}{2 \cdot 2} : 2

x = \frac{- ( - 1 ) - 7}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{2}

a (x + 5) = x^{2} + 3 x - 10

2 x^{2} - 3 = 29

5 = (b + 1)^{2} + b^{2}

10 x^{2} + 3 x + 3 = 5

(x - 6) (x - 6) = 0

What are the solutions to the equation 0=2x^2-x-6 ?
The solutions to the equation 0=2x^2-x-6 are x=2,x=-3/2
Find the zeros of 0=2x^2-x-6
The zeros of 0=2x^2-x-6 are x=2,x=-3/2