What are the solutions to the equation 10x^2+3x+3=5 ?

The solutions to the equation 10x^2+3x+3=5 are x=(-3+sqrt(89))/(20),x=(-3-sqrt(89))/(20)

Find the zeros of 10x^2+3x+3=5

The zeros of 10x^2+3x+3=5 are x=(-3+sqrt(89))/(20),x=(-3-sqrt(89))/(20)

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10 x^{2} + 3 x + 3 = 5

x = \frac{- 3 + 89}{20}, x = \frac{- 3 - 89}{20}

Decimal Notation

x = 0.32169 \dots, x = - 0.62169 \dots

Solution steps

10 x^{2} + 3 x + 3 = 5

Move

5

to the left side

10 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 10 ( - 2 )}{2 \cdot 10}

3^{2} - 4 \cdot 10 (- 2) = 89

x_{1, 2} = \frac{- 3 \pm 89}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 3 + 89}{2 \cdot 10}, x_{2} = \frac{- 3 - 89}{2 \cdot 10}

x = \frac{- 3 + 89}{2 \cdot 10} : \frac{- 3 + 89}{20}

x = \frac{- 3 - 89}{2 \cdot 10} : \frac{- 3 - 89}{20}

The solutions to the quadratic equation are:

x = \frac{- 3 + 89}{20}, x = \frac{- 3 - 89}{20}

(x - 6) (x - 6) = 0

36 = m^{2}

0 = - x^{2} + x + 2

- 6 x^{2} - 24 x + 564 = 0

(36 - 2 r)^{2} = 36 + 2 r

What are the solutions to the equation 10x^2+3x+3=5 ?
The solutions to the equation 10x^2+3x+3=5 are x=(-3+sqrt(89))/(20),x=(-3-sqrt(89))/(20)
Find the zeros of 10x^2+3x+3=5
The zeros of 10x^2+3x+3=5 are x=(-3+sqrt(89))/(20),x=(-3-sqrt(89))/(20)