What are the solutions to the equation 5x^2+48x+27=(5x+3) ?

The solutions to the equation 5x^2+48x+27=(5x+3) are x=-3/5 ,x=-8

Find the zeros of 5x^2+48x+27=(5x+3)

The zeros of 5x^2+48x+27=(5x+3) are x=-3/5 ,x=-8

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5 x^{2} + 48 x + 27 = (5 x + 3)

x = - \frac{3}{5}, x = - 8

Decimal Notation

x = - 0.6, x = - 8

Solution steps

5 x^{2} + 48 x + 27 = (5 x + 3)

Refine

5 x^{2} + 48 x + 27 = 5 x + 3

Move

3

to the left side

5 x^{2} + 48 x + 24 = 5 x

Move

5 x

to the left side

5 x^{2} + 43 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 43 \pm 4 3 ^{2} - 4 \cdot 5 \cdot 24}{2 \cdot 5}

4 3^{2} - 4 \cdot 5 \cdot 24 = 37

x_{1, 2} = \frac{- 43 \pm 37}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 43 + 37}{2 \cdot 5}, x_{2} = \frac{- 43 - 37}{2 \cdot 5}

x = \frac{- 43 + 37}{2 \cdot 5} : - \frac{3}{5}

x = \frac{- 43 - 37}{2 \cdot 5} : - 8

The solutions to the quadratic equation are:

x = - \frac{3}{5}, x = - 8

6 (x - 3) - 6 (x - 4) = (x - 4) (x - 3)

80 \cdot 10 = \frac{v ^{2}}{2}

16.1 t^{2} - 200 t - 200 = 0

3 x^{2} - 6 x - 244 = 0

x^{2} - 3 x = 0

What are the solutions to the equation 5x^2+48x+27=(5x+3) ?
The solutions to the equation 5x^2+48x+27=(5x+3) are x=-3/5 ,x=-8
Find the zeros of 5x^2+48x+27=(5x+3)
The zeros of 5x^2+48x+27=(5x+3) are x=-3/5 ,x=-8