What are the solutions to the equation 3x^2-6x-244=0 ?

The solutions to the equation 3x^2-6x-244=0 are x=(3+sqrt(741))/3 ,x=(3-sqrt(741))/3

Find the zeros of 3x^2-6x-244=0

The zeros of 3x^2-6x-244=0 are x=(3+sqrt(741))/3 ,x=(3-sqrt(741))/3

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3 x^{2} - 6 x - 244 = 0

x = \frac{3 + 741}{3}, x = \frac{3 - 741}{3}

Decimal Notation

x = 10.07377 \dots, x = - 8.07377 \dots

Solution steps

3 x^{2} - 6 x - 244 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 244 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 244) = 2741

x_{1, 2} = \frac{- ( - 6 ) \pm 2 741}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 741}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 741}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 741}{2 \cdot 3} : \frac{3 + 741}{3}

x = \frac{- ( - 6 ) - 2 741}{2 \cdot 3} : \frac{3 - 741}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 741}{3}, x = \frac{3 - 741}{3}

x^{2} - 3 x = 0

6 x (x - 1) = 35 - 7 x

x, f (x + 1) = x^{2} - x

a = (2 x + 6) \cdot (2 x + 6)

\frac{1}{2} x^{2} + 2 x + 1 = 0

What are the solutions to the equation 3x^2-6x-244=0 ?
The solutions to the equation 3x^2-6x-244=0 are x=(3+sqrt(741))/3 ,x=(3-sqrt(741))/3
Find the zeros of 3x^2-6x-244=0
The zeros of 3x^2-6x-244=0 are x=(3+sqrt(741))/3 ,x=(3-sqrt(741))/3