What are the solutions to the equation 6x(x-1)=35-7x ?

The solutions to the equation 6x(x-1)=35-7x are x= 7/3 ,x=-5/2

Find the zeros of 6x(x-1)=35-7x

The zeros of 6x(x-1)=35-7x are x= 7/3 ,x=-5/2

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6 x (x - 1) = 35 - 7 x

x = \frac{7}{3}, x = - \frac{5}{2}

Decimal Notation

x = 2.33333 \dots, x = - 2.5

Solution steps

6 x (x - 1) = 35 - 7 x

Expand

6 x (x - 1) : 6 x^{2} - 6 x

6 x^{2} - 6 x = 35 - 7 x

Move

7 x

to the left side

6 x^{2} + x = 35

Move

35

to the left side

6 x^{2} + x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 35 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 35) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 6}, x_{2} = \frac{- 1 - 29}{2 \cdot 6}

x = \frac{- 1 + 29}{2 \cdot 6} : \frac{7}{3}

x = \frac{- 1 - 29}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{5}{2}

x, f (x + 1) = x^{2} - x

a = (2 x + 6) \cdot (2 x + 6)

\frac{1}{2} x^{2} + 2 x + 1 = 0

2 x^{2} + 5 = 3

10 x^{2} - 256 = 300

What are the solutions to the equation 6x(x-1)=35-7x ?
The solutions to the equation 6x(x-1)=35-7x are x= 7/3 ,x=-5/2
Find the zeros of 6x(x-1)=35-7x
The zeros of 6x(x-1)=35-7x are x= 7/3 ,x=-5/2