What are the solutions to the equation 6x^2-29x=0 ?

The solutions to the equation 6x^2-29x=0 are x= 29/6 ,x=0

Find the zeros of 6x^2-29x=0

The zeros of 6x^2-29x=0 are x= 29/6 ,x=0

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6 x^{2} - 29 x = 0

x = \frac{29}{6}, x = 0

Decimal Notation

x = 4.83333 \dots, x = 0

Solution steps

6 x^{2} - 29 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 29)^{2} - 4 \cdot 6 \cdot 0 = 29

x_{1, 2} = \frac{- ( - 29 ) \pm 29}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 29}{2 \cdot 6}, x_{2} = \frac{- ( - 29 ) - 29}{2 \cdot 6}

x = \frac{- ( - 29 ) + 29}{2 \cdot 6} : \frac{29}{6}

x = \frac{- ( - 29 ) - 29}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

x = \frac{29}{6}, x = 0

(x - 1)^{2} + (7 - 2 x)^{2} = 10

(x + 5) (2 x - 3) = 2 (x + 1)

(3 x - 2) (x + 1) = 8 x - 3

3 x^{2} + 5 x - 28 = 0

(1 + 5 x)^{2} = (4 x - 1) 2^{2} + 9 x (x - 2)

What are the solutions to the equation 6x^2-29x=0 ?
The solutions to the equation 6x^2-29x=0 are x= 29/6 ,x=0
Find the zeros of 6x^2-29x=0
The zeros of 6x^2-29x=0 are x= 29/6 ,x=0