What are the solutions to the equation -c^2+c+6=0 ?

The solutions to the equation -c^2+c+6=0 are c=-2,c=3

Find the zeros of -c^2+c+6=0

The zeros of -c^2+c+6=0 are c=-2,c=3

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- c^{2} + c + 6 = 0

c = - 2, c = 3

Solution steps

- c^{2} + c + 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 6 = 5

c_{1, 2} = \frac{- 1 \pm 5}{2 ( - 1 )}

Separate the solutions

c_{1} = \frac{- 1 + 5}{2 ( - 1 )}, c_{2} = \frac{- 1 - 5}{2 ( - 1 )}

c = \frac{- 1 + 5}{2 ( - 1 )} : - 2

c = \frac{- 1 - 5}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

c = - 2, c = 3

20 (p^{2} - 1) = 9 p

- d^{2} + 200 = d^{2} - 42

5 x^{2} - 29 x + 20 = 0

2 x^{2} = - 7 x - 9

2 x^{2} = - 7 x + 4

What are the solutions to the equation -c^2+c+6=0 ?
The solutions to the equation -c^2+c+6=0 are c=-2,c=3
Find the zeros of -c^2+c+6=0
The zeros of -c^2+c+6=0 are c=-2,c=3