What are the solutions to the equation 2x^2=-2 ?

The solutions to the equation 2x^2=-2 are x=i,x=-i

Find the zeros of 2x^2=-2

The zeros of 2x^2=-2 are x=i,x=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} = - 2

x = i, x = - i

Solution steps

2 x^{2} = - 2

Divide both sides by

2

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

8 x^{2} + 1 = 22 x + 1

4 (x + 3)^{2} = 25 (x - 2)^{2}

x, x^{2} - 6 x y + y^{2} = 0

x, 2 p x^{2} + 3 x - 2 - 5 p = 0

25 (x + 1) = \frac{7}{2} x^{2}

What are the solutions to the equation 2x^2=-2 ?
The solutions to the equation 2x^2=-2 are x=i,x=-i
Find the zeros of 2x^2=-2
The zeros of 2x^2=-2 are x=i,x=-i