What are the solutions to the equation 4x^2+18x-30=0 ?

The solutions to the equation 4x^2+18x-30=0 are x=(-9+sqrt(201))/4 ,x=-(9+sqrt(201))/4

Find the zeros of 4x^2+18x-30=0

The zeros of 4x^2+18x-30=0 are x=(-9+sqrt(201))/4 ,x=-(9+sqrt(201))/4

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4 x^{2} + 18 x - 30 = 0

x = \frac{- 9 + 201}{4}, x = - \frac{9 + 201}{4}

Decimal Notation

x = 1.29436 \dots, x = - 5.79436 \dots

Solution steps

4 x^{2} + 18 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 4 ( - 30 )}{2 \cdot 4}

1 8^{2} - 4 \cdot 4 (- 30) = 2201

x_{1, 2} = \frac{- 18 \pm 2 201}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 18 + 2 201}{2 \cdot 4}, x_{2} = \frac{- 18 - 2 201}{2 \cdot 4}

x = \frac{- 18 + 2 201}{2 \cdot 4} : \frac{- 9 + 201}{4}

x = \frac{- 18 - 2 201}{2 \cdot 4} : - \frac{9 + 201}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 201}{4}, x = - \frac{9 + 201}{4}

4 x = - 4 x^{2}

x^{2} - 2 x - 1 = 0

x, f (2 x + 1) = 1 - (x - 3)^{2}

x, 12 x^{2} = 3 x

p^{2} - 169 = 0

What are the solutions to the equation 4x^2+18x-30=0 ?
The solutions to the equation 4x^2+18x-30=0 are x=(-9+sqrt(201))/4 ,x=-(9+sqrt(201))/4
Find the zeros of 4x^2+18x-30=0
The zeros of 4x^2+18x-30=0 are x=(-9+sqrt(201))/4 ,x=-(9+sqrt(201))/4