What are the solutions to the equation -6x^2-96x+355=-12x+1 ?

The solutions to the equation -6x^2-96x+355=-12x+1 are x=-7-6sqrt(3),x=6sqrt(3)-7

Find the zeros of -6x^2-96x+355=-12x+1

The zeros of -6x^2-96x+355=-12x+1 are x=-7-6sqrt(3),x=6sqrt(3)-7

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- 6 x^{2} - 96 x + 355 = - 12 x + 1

x = - 7 - 63, x = 63 - 7

Decimal Notation

x = - 17.39230 \dots, x = 3.39230 \dots

Solution steps

- 6 x^{2} - 96 x + 355 = - 12 x + 1

Move

1

to the left side

- 6 x^{2} - 96 x + 354 = - 12 x

Move

12 x

to the left side

- 6 x^{2} - 84 x + 354 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 84 ) \pm ( - 84 ) ^{2} - 4 ( - 6 ) \cdot 354}{2 ( - 6 )}

(- 84)^{2} - 4 (- 6) \cdot 354 = 723

x_{1, 2} = \frac{- ( - 84 ) \pm 72 3}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 84 ) + 72 3}{2 ( - 6 )}, x_{2} = \frac{- ( - 84 ) - 72 3}{2 ( - 6 )}

x = \frac{- ( - 84 ) + 72 3}{2 ( - 6 )} : - 7 - 63

x = \frac{- ( - 84 ) - 72 3}{2 ( - 6 )} : 63 - 7

The solutions to the quadratic equation are:

x = - 7 - 63, x = 63 - 7

2 x^{2} - 3 x - 1 = 0

x^{2} - 500 = 125

x^{2} + 2 x - 48 = 0

(x - 5)^{2} - (x - 5) - 30 = 0

a, a^{2} - a + b c = 0

What are the solutions to the equation -6x^2-96x+355=-12x+1 ?
The solutions to the equation -6x^2-96x+355=-12x+1 are x=-7-6sqrt(3),x=6sqrt(3)-7
Find the zeros of -6x^2-96x+355=-12x+1
The zeros of -6x^2-96x+355=-12x+1 are x=-7-6sqrt(3),x=6sqrt(3)-7