What are the solutions to the equation (x-5)^2-(x-5)-30=0 ?

The solutions to the equation (x-5)^2-(x-5)-30=0 are x=11,x=0

Find the zeros of (x-5)^2-(x-5)-30=0

The zeros of (x-5)^2-(x-5)-30=0 are x=11,x=0

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(x - 5)^{2} - (x - 5) - 30 = 0

x = 11, x = 0

Solution steps

(x - 5)^{2} - (x - 5) - 30 = 0

Expand

(x - 5)^{2} - (x - 5) - 30 : x^{2} - 11 x

x^{2} - 11 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 0 = 11

x_{1, 2} = \frac{- ( - 11 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 11}{2 \cdot 1}

x = \frac{- ( - 11 ) + 11}{2 \cdot 1} : 11

x = \frac{- ( - 11 ) - 11}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 11, x = 0

a, a^{2} - a + b c = 0

2 x^{2} + x - \frac{1}{8} = 0

- 5 x^{2} + 5 x - 5 = 0

(2 x - 2)^{2} - (x + 3)^{2} = - 5

y = 2 y^{2}

What are the solutions to the equation (x-5)^2-(x-5)-30=0 ?
The solutions to the equation (x-5)^2-(x-5)-30=0 are x=11,x=0
Find the zeros of (x-5)^2-(x-5)-30=0
The zeros of (x-5)^2-(x-5)-30=0 are x=11,x=0