What are the solutions to the equation y=2y^2 ?

The solutions to the equation y=2y^2 are y= 1/2 ,y=0

Find the zeros of y=2y^2

The zeros of y=2y^2 are y= 1/2 ,y=0

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y = 2 y^{2}

y = \frac{1}{2}, y = 0

Decimal Notation

y = 0.5, y = 0

Solution steps

y = 2 y^{2}

Switch sides

2 y^{2} = y

Move

y

to the left side

2 y^{2} - y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 \cdot 0 = 1

y_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 2}, y_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 2}

y = \frac{- ( - 1 ) + 1}{2 \cdot 2} : \frac{1}{2}

y = \frac{- ( - 1 ) - 1}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

y = \frac{1}{2}, y = 0

a x^{2} + x + c = 0

2 x^{2} + 4 x = 3 + 3 x^{2}

\frac{1}{2} (2 x - 3)^{2} + 1 = 11

3 x^{2} - 48 x = - 159

5 x = 3 x^{2}

What are the solutions to the equation y=2y^2 ?
The solutions to the equation y=2y^2 are y= 1/2 ,y=0
Find the zeros of y=2y^2
The zeros of y=2y^2 are y= 1/2 ,y=0