What are the solutions to the equation 1/2 (2x-3)^2+1=11 ?

The solutions to the equation 1/2 (2x-3)^2+1=11 are x=(2sqrt(5)+3)/2 ,x=(-2sqrt(5)+3)/2

Find the zeros of 1/2 (2x-3)^2+1=11

The zeros of 1/2 (2x-3)^2+1=11 are x=(2sqrt(5)+3)/2 ,x=(-2sqrt(5)+3)/2

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\frac{1}{2} (2 x - 3)^{2} + 1 = 11

x = \frac{2 5 + 3}{2}, x = \frac{- 2 5 + 3}{2}

Decimal Notation

x = 3.73606 \dots, x = - 0.73606 \dots

Solution steps

\frac{1}{2} (2 x - 3)^{2} + 1 = 11

Move

1

to the right side

\frac{1}{2} (2 x - 3)^{2} = 10

Multiply both sides by

2

(2 x - 3)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 20 : x = \frac{2 5 + 3}{2}

Solve

2 x - 3 = - 20 : x = \frac{- 2 5 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{2 5 + 3}{2}, x = \frac{- 2 5 + 3}{2}

3 x^{2} - 48 x = - 159

5 x = 3 x^{2}

(2 x - 3)^{2} = 4

G (x) = 7 x^{2} + 5 x - 4

6 \cdot x^{2} + 6 \cdot x - 120 = 0

What are the solutions to the equation 1/2 (2x-3)^2+1=11 ?
The solutions to the equation 1/2 (2x-3)^2+1=11 are x=(2sqrt(5)+3)/2 ,x=(-2sqrt(5)+3)/2
Find the zeros of 1/2 (2x-3)^2+1=11
The zeros of 1/2 (2x-3)^2+1=11 are x=(2sqrt(5)+3)/2 ,x=(-2sqrt(5)+3)/2