What are the solutions to the equation 6*x^2+6*x-120=0 ?

The solutions to the equation 6*x^2+6*x-120=0 are x=4,x=-5

Find the zeros of 6*x^2+6*x-120=0

The zeros of 6*x^2+6*x-120=0 are x=4,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 \cdot x^{2} + 6 \cdot x - 120 = 0

x = 4, x = - 5

Solution steps

6 x^{2} + 6 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 120 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 120) = 54

x_{1, 2} = \frac{- 6 \pm 54}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 54}{2 \cdot 6}, x_{2} = \frac{- 6 - 54}{2 \cdot 6}

x = \frac{- 6 + 54}{2 \cdot 6} : 4

x = \frac{- 6 - 54}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

- z^{2} = 4

5 x^{2} + 2 = 2 x

t^{2} - 3 t - 7 = 0

x, E = \frac{1}{2} k x^{2}

x, t (x) = - x^{2} + 4 x - 5

What are the solutions to the equation 6*x^2+6*x-120=0 ?
The solutions to the equation 6*x^2+6*x-120=0 are x=4,x=-5
Find the zeros of 6*x^2+6*x-120=0
The zeros of 6*x^2+6*x-120=0 are x=4,x=-5