What are the solutions to the equation 2x^2-10x+8=0 ?

The solutions to the equation 2x^2-10x+8=0 are x=4,x=1

Find the zeros of 2x^2-10x+8=0

The zeros of 2x^2-10x+8=0 are x=4,x=1

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2 x^{2} - 10 x + 8 = 0

x = 4, x = 1

Solution steps

2 x^{2} - 10 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 8 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 2}

x = \frac{- ( - 10 ) + 6}{2 \cdot 2} : 4

x = \frac{- ( - 10 ) - 6}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

a^{2} - 8 a + 7

- 7 + 1

∣ 1 - 2 x ∣ < 9

x^{2} + 2 x + 6 = 0

\frac{2}{7} v + \frac{4}{5} = \frac{6}{5} v - \frac{4}{5}

What are the solutions to the equation 2x^2-10x+8=0 ?
The solutions to the equation 2x^2-10x+8=0 are x=4,x=1
Find the zeros of 2x^2-10x+8=0
The zeros of 2x^2-10x+8=0 are x=4,x=1