What are the solutions to the equation 4x^2+32x+28=0 ?

The solutions to the equation 4x^2+32x+28=0 are x=-1,x=-7

Find the zeros of 4x^2+32x+28=0

The zeros of 4x^2+32x+28=0 are x=-1,x=-7

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4 x^{2} + 32 x + 28 = 0

x = - 1, x = - 7

Solution steps

4 x^{2} + 32 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 4 \cdot 28}{2 \cdot 4}

3 2^{2} - 4 \cdot 4 \cdot 28 = 24

x_{1, 2} = \frac{- 32 \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 32 + 24}{2 \cdot 4}, x_{2} = \frac{- 32 - 24}{2 \cdot 4}

x = \frac{- 32 + 24}{2 \cdot 4} : - 1

x = \frac{- 32 - 24}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

4 y^{2} - 6 y + 9 = 0

y, x = a y^{2} + b y + c

11 x^{2} - 7 x + 1 = 0

\frac{x ^{2}}{2} + 2 x - 6 = 0

x, 3 x^{2} + 4 y^{2} + 3 = 0

What are the solutions to the equation 4x^2+32x+28=0 ?
The solutions to the equation 4x^2+32x+28=0 are x=-1,x=-7
Find the zeros of 4x^2+32x+28=0
The zeros of 4x^2+32x+28=0 are x=-1,x=-7