What are the solutions to the equation 4x^2+15x=0 ?

The solutions to the equation 4x^2+15x=0 are x=0,x=-15/4

Find the zeros of 4x^2+15x=0

The zeros of 4x^2+15x=0 are x=0,x=-15/4

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4 x^{2} + 15 x = 0

x = 0, x = - \frac{15}{4}

Decimal Notation

x = 0, x = - 3.75

Solution steps

4 x^{2} + 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

1 5^{2} - 4 \cdot 4 \cdot 0 = 15

x_{1, 2} = \frac{- 15 \pm 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 15 + 15}{2 \cdot 4}, x_{2} = \frac{- 15 - 15}{2 \cdot 4}

x = \frac{- 15 + 15}{2 \cdot 4} : 0

x = \frac{- 15 - 15}{2 \cdot 4} : - \frac{15}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{15}{4}

(x + 1) (x^{2} - x + 1) = (x - 1)^{3}

x, g (x + 2) = x^{2} - 10 x - 3

x (2 x - 9) = 0

3 y^{2} + 7 y + 10 = 3

2 t^{2} + 5 = 7 t

What are the solutions to the equation 4x^2+15x=0 ?
The solutions to the equation 4x^2+15x=0 are x=0,x=-15/4
Find the zeros of 4x^2+15x=0
The zeros of 4x^2+15x=0 are x=0,x=-15/4