What are the solutions to the equation factor 2t^2+5=7t ?

The solutions to the equation factor 2t^2+5=7t are t=1,t= 5/2

Find the zeros of factor 2t^2+5=7t

The zeros of factor 2t^2+5=7t are t=1,t= 5/2

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2 t^{2} + 5 = 7 t

t = 1, t = \frac{5}{2}

Decimal Notation

t = 1, t = 2.5

Solution steps

2 t^{2} + 5 = 7 t

Move

7 t

to the left side

2 t^{2} + 5 - 7 t = 0

Write in the standard form

a x^{2} + b x + c = 0

2 t^{2} - 7 t + 5 = 0

Factor

2 t^{2} - 7 t + 5 : (t - 1) (2 t - 5)

(t - 1) (2 t - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t - 1 = 0 or 2 t - 5 = 0

Solve

t - 1 = 0 : t = 1

Solve

2 t - 5 = 0 : t = \frac{5}{2}

The solutions to the quadratic equation are:

t = 1, t = \frac{5}{2}

x^{2} + 6 x - 35 = 0

x, (5 x + 8) (12 - 12 x) = 0

z^{2} + 5 z + 3 = 0

x, 2 x^{2} + 5 x - 8 = 0

4 x (x - 4) = 7

What are the solutions to the equation factor 2t^2+5=7t ?
The solutions to the equation factor 2t^2+5=7t are t=1,t= 5/2
Find the zeros of factor 2t^2+5=7t
The zeros of factor 2t^2+5=7t are t=1,t= 5/2