What are the solutions to the equation solvefor x,(5x+8)(12-12x)=0 ?

The solutions to the equation solvefor x,(5x+8)(12-12x)=0 are x=-8/5 ,x=1

Find the zeros of solvefor x,(5x+8)(12-12x)=0

The zeros of solvefor x,(5x+8)(12-12x)=0 are x=-8/5 ,x=1

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solve for

x, (5 x + 8) (12 - 12 x) = 0

x = - \frac{8}{5}, x = 1

Decimal Notation

x = - 1.6, x = 1

Solution steps

(5 x + 8) (12 - 12 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 8 = 0 or 12 - 12 x = 0

Solve

5 x + 8 = 0 : x = - \frac{8}{5}

Solve

12 - 12 x = 0 : x = 1

The solutions to the quadratic equation are:

x = - \frac{8}{5}, x = 1

z^{2} + 5 z + 3 = 0

x, 2 x^{2} + 5 x - 8 = 0

4 x (x - 4) = 7

- 15 t^{2} + 2 = - 7 t

(x - 4) (x + 6) - (x - 3) 2 = 15

What are the solutions to the equation solvefor x,(5x+8)(12-12x)=0 ?
The solutions to the equation solvefor x,(5x+8)(12-12x)=0 are x=-8/5 ,x=1
Find the zeros of solvefor x,(5x+8)(12-12x)=0
The zeros of solvefor x,(5x+8)(12-12x)=0 are x=-8/5 ,x=1