What are the solutions to the equation -x^2-17x+53=-2x^2+3 ?

The solutions to the equation -x^2-17x+53=-2x^2+3 are x=(17+sqrt(89))/2 ,x=(17-sqrt(89))/2

Find the zeros of -x^2-17x+53=-2x^2+3

The zeros of -x^2-17x+53=-2x^2+3 are x=(17+sqrt(89))/2 ,x=(17-sqrt(89))/2

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- x^{2} - 17 x + 53 = - 2 x^{2} + 3

x = \frac{17 + 89}{2}, x = \frac{17 - 89}{2}

Decimal Notation

x = 13.21699 \dots, x = 3.78300 \dots

Solution steps

- x^{2} - 17 x + 53 = - 2 x^{2} + 3

Move

3

to the left side

- x^{2} - 17 x + 50 = - 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} - 17 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 50 = 89

x_{1, 2} = \frac{- ( - 17 ) \pm 89}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 89}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 89}{2 \cdot 1}

x = \frac{- ( - 17 ) + 89}{2 \cdot 1} : \frac{17 + 89}{2}

x = \frac{- ( - 17 ) - 89}{2 \cdot 1} : \frac{17 - 89}{2}

The solutions to the quadratic equation are:

x = \frac{17 + 89}{2}, x = \frac{17 - 89}{2}

y^{2} - 14 y = - 30

5 x^{2} + 7 = - 8

5 t^{2} - 60 t + 27 = 0

(x - 2)^{2} - 5 = - 6

x, f (x + 3) = 3 x^{2} + 4 x - 2

What are the solutions to the equation -x^2-17x+53=-2x^2+3 ?
The solutions to the equation -x^2-17x+53=-2x^2+3 are x=(17+sqrt(89))/2 ,x=(17-sqrt(89))/2
Find the zeros of -x^2-17x+53=-2x^2+3
The zeros of -x^2-17x+53=-2x^2+3 are x=(17+sqrt(89))/2 ,x=(17-sqrt(89))/2